4x^2-88x+84=0

Solution for 4x^2-88x+84=0 equation:

4x^2-88x+84=0

a = 4; b = -88; c = +84;
Δ = b2-4ac
Δ = -882-4·4·84
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-80}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+80}{2*4}=\frac{168}{8}
=21
$